fix: 直线 hover 跟随的贴卡扭曲——stepPath 半径自适应(min(r,|dy|/2,dx/3)),微浮 3px 收为 r1.5 浅弯,两段弧不再交叠倒置

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cqh963852 committed 2026-10-08 13:27:25 +08:00
1 parent c11f33c6b7
commit 85673aa80a
1 file changed
+8 -4
+8 -4
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@@ -16,14 +16,18 @@ export interface LaneNode {
y: number // 卡中线 y y: number // 卡中线 y
} }
/** 水平出发 → R8 双弯直角步进 → 水平到达;同 y 时直线 */ /* 水平出发 → 双弯直角步进 → 水平到达;同 y 时直线。
* 半径自适应:垂直空间 |dy| 或水平空间不足 2r 时收缩(如 hover 微浮 dy=3),
* 否则两段弧会交叠倒置,在贴卡处扭曲成折返。 */
function stepPath(x0: number, y0: number, x1: number, y1: number, r = 8): string { function stepPath(x0: number, y0: number, x1: number, y1: number, r = 8): string {
if (Math.abs(y1 - y0) < 1) return `M ${x0} ${y0} H ${x1}` const dyAbs = Math.abs(y1 - y0)
if (dyAbs < 1) return `M ${x0} ${y0} H ${x1}`
const rr = Math.max(0.5, Math.min(r, dyAbs / 2, (x1 - x0) / 3))
const down = y1 > y0 const down = y1 > y0
const sweep1 = down ? 1 : 0 const sweep1 = down ? 1 : 0
const sweep2 = down ? 0 : 1 const sweep2 = down ? 0 : 1
const cornerX = Math.max(x0 + r, x1 - 2 * r) const cornerX = Math.max(x0 + rr, x1 - 2 * rr)
return `M ${x0} ${y0} H ${cornerX} A ${r} ${r} 0 0 ${sweep1} ${cornerX + r} ${y0 + (down ? r : -r)} V ${y1 - (down ? r : -r)} A ${r} ${r} 0 0 ${sweep2} ${cornerX + 2 * r} ${y1} H ${x1}` return `M ${x0} ${y0} H ${cornerX} A ${rr} ${rr} 0 0 ${sweep1} ${cornerX + rr} ${y0 + (down ? rr : -rr)} V ${y1 - (down ? rr : -rr)} A ${rr} ${rr} 0 0 ${sweep2} ${cornerX + 2 * rr} ${y1} H ${x1}`
} }
const HOVER_LIFT = -3 // 与 MemphisCard hover:-translate-y-[3px] 一致 const HOVER_LIFT = -3 // 与 MemphisCard hover:-translate-y-[3px] 一致